[kaffe] Re: Computing remainders
robilad at yahoo.com
Sun Jun 29 03:51:01 PDT 2003
--- Dalibor Topic <robilad at yahoo.com> wrote:
> Sounds good to me. That's similar to the route I'd like to go for the
> interpreter as well.
> 1. make the current special case (#ifdef LONG_MODULO_BROKEN) the only case.
> That should fix powerpc, x86 and m68k.
> 2. remove the according configure.in checks. since they become unnecessary.
> 3. write configure.in checks to see if C / with negative args rounds to 0
> 4. write configure.in checks to see if C % with negative args is negative
> 5. implement Java / and % on those platforms where the checks above fail
> my slow div_t based implementation.
> 6. put the division and remainder code in its own header file
I had a brief look over gcc 3.2 internals docs:
The result of a `TRUNC_DIV_EXPR' is always rounded towards zero.
The `TRUNC_MOD_EXPR' of two operands `a' and `b' is always `a -
a/b' where the division is as if computed by a `TRUNC_DIV_EXPR'.
so as long as we are only using the gcc, there's no need for steps 3-6 ;)
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